(6x+5)(x^2-4x+1)=

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Solution for (6x+5)(x^2-4x+1)= equation: 


Simplifying
(6x + 5)(x2 + -4x + 1) = 0

Reorder the terms:
(5 + 6x)(x2 + -4x + 1) = 0

Reorder the terms:
(5 + 6x)(1 + -4x + x2) = 0

Multiply (5 + 6x) * (1 + -4x + x2)
(5(1 + -4x + x2) + 6x * (1 + -4x + x2)) = 0
((1 * 5 + -4x * 5 + x2 * 5) + 6x * (1 + -4x + x2)) = 0
((5 + -20x + 5x2) + 6x * (1 + -4x + x2)) = 0
(5 + -20x + 5x2 + (1 * 6x + -4x * 6x + x2 * 6x)) = 0
(5 + -20x + 5x2 + (6x + -24x2 + 6x3)) = 0

Reorder the terms:
(5 + -20x + 6x + 5x2 + -24x2 + 6x3) = 0

Combine like terms: -20x + 6x = -14x
(5 + -14x + 5x2 + -24x2 + 6x3) = 0

Combine like terms: 5x2 + -24x2 = -19x2
(5 + -14x + -19x2 + 6x3) = 0

Solving
5 + -14x + -19x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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